Challenging Physics Question!! 10 POINTS?

Question

A sphere of mass 0.3 grams is suspended from a 30cm cord. A steady horrizontal breeze pushes the sphere so that is makes an angle of 37 degrees with the vertical. Find the magnitude of the wind force and the tension in the cord.

Best answer gets 10 points!!
Please show how you got to the answer
Have Fun!!

Answer 1

Well, I am not gonna answer the whole problem. Tension = Weight
Tension at 37degree angle T = W cos37 + W sin37

Answer 2

The weight of the sphere is W = mg = 3 x 10^-4 kg * 9.8 m/s^2 = 2.94 x 10^-3 N

At 37 degrees, the component of Tension in the vertical direction must be equal to the weight of the sphere, as there are no other forces in the vertical direction. Thus, Ty = 2.94 * 10^-3 N

The tension in the cord by trigonometry (since Ty= T cos 37) is T = 3.68 x 10^-3 N

The component of Tension in the horizontal direction is equal to the force due to he wind on the sphere.

Tx = T sin 37 = 2.22 x 10^-3 N

Answer 3

Two answers given here are correct. But I would like to answer it this way. The ball is at rest, so according to Newton's laws, No net force acts on it. But there are three forces acting on the ball E, due to earth downwards, FW due to wind in horizontal dierction and Tension, T which is a self adjusting force acting upwards at an angle 37 degrees with vertical direction. 37 degrees gives you a right triangle of sides proportional to 3, 4 and 5, Hence sin37 = 3/5, cos37 4/5 and tan 37 = 3/4

So T cos 37 = E and T sin 37 = WF
or tan37=WF/E or WF =E tan37 =0.0003x9.8x(3/4)= 0.002205 N

T = 0.002205/sin37 = (0.002205x5)/3 = 0.003675 N

Answer 4

Well, isn't this fun?

ok, look, the string is still HOLDING UP the sphere right?

So, the VERTICAL component of the tension includes the entire weight of the sphere plus the displacement force.

So, you know one side of the triangle of forces and the angel.

If you draw the triangle of fources, the VERTICAL force is 0.3 * 9.8m/sec^2 Right?

and that is call the verical force Fv Call the tension Ft and the horizontal force Fh

now Fh / Fv = tan(37 degrees)

So, Fh = tan(37) * Fv -- so, that's the horizontal force...

and Fv = Ft * cos(37 degrees)

So, Ft = Fv / cos(37)

and you're done?

Answer 5

Start with your free body diagram and go from there.
Do your summation of forces in the x and y and if necessary a summation of your moments. Once you get the same amount of equations as amount of unknowns, just put it all in a simultaneous solution solver and there you go.

Answer 6

I am happy with only 2 marks. lol. and who cares about the cord and sphere anyway no offence to the one who does acually cares.