A sphere of mass 0.3 grams is suspended from a 30cm cord. S steady horrizontal breeze pshes the sphere so that is makes an angle of 37 degrees with the vertical. Find the magnitude of the wind force and the tension in the cord.
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2006-12-02 12:37:48 · 6 answers · asked by Brody 3 in Science & Mathematics ➔ Physics
well i wud say your crazy
2006-12-02 12:41:18 · answer #1 · answered by michaeljoyzer 2 · 0⤊ 2⤋
the burden of the sector is W = mg = 3 x 10^-4 kg * 9.8 m/s^2 = 2.ninety 4 x 10^-3 N At 37 tiers, the element of stress in the vertical course could be equivalent to the burden of the sector, as there are not the different forces in the vertical course. to that end, Ty = 2.ninety 4 * 10^-3 N the stress in the twine by trigonometry (on account that Ty= T cos 37) is T = 3.sixty 8 x 10^-3 N The element of stress in the horizontal course is comparable to the stress as a results of he wind on the sector. Tx = T sin 37 = 2.22 x 10^-3 N
2016-10-17 15:18:23 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Wind Force= 0.3x9.8xtan37 /100 = 0.022N
Tension=0.3x9.8/100/cos 37 = 0.037 N
2006-12-02 17:29:09 · answer #3 · answered by t y 2 · 0⤊ 0⤋
don't know the answer to that one but if you meet the gal hang on tight sounds like a keeper !!!
2006-12-02 12:47:31 · answer #4 · answered by Anonymous · 0⤊ 1⤋
2.25 N
4.12 m/s
2006-12-02 14:51:16 · answer #5 · answered by zzzzzzzzz 3 · 0⤊ 0⤋
There is no challenge.
2006-12-02 14:18:38 · answer #6 · answered by Pearlsawme 7 · 0⤊ 1⤋