Help with a parallel lines math problem?

Question

Find an equation of the line containing (4,-2) and parallel to the line containing (3,-5) and (-2,7) How do you solve this problem. I know you need to find slope (m) but am not sure how to.

Answer 1

step 1: Find slope 7-(-5)/-2-3 = -12/5
step 2: plug into point from other line into point-slope formula equation. y-y1 = m(x-x1)
y-(-2) = -12/5(x-4) then get rid of fraction
5(y+2) = 5(-12/5)(x-4)
5y +10 = -12x +48
12x + 5y = 38 standard form: Ax + By = C

Answer 2

Slope of a line is the rise of Y for every increase in X. In another words, if you take two coordinates of the line, figure out the difference of Y, figure out the difference of X, divide first by second, you'll have it.

In this example,
m = (7 - -5)/(-2 - 3)
m = 12 / - 5
m = -12/5

Then you have a line that passes though (4 -2)
and parallel to the first line (same slope)
That means the line must satisfy the equation like this:
y = mx + k
-2 = (-12/5)4 + k
-2 = -48/5 + k
-2 + 48/5 = k
k = -10/5 + 48/5
k = 38/5

Finally, the formula is
y = (-12/5)x + 38/5

Answer 3

The slope of a line joining two pts. is m=(y1-y2)/(x1-x2) where the coordinates of the pts. are (x1,y1) and (x2,y2) respy. In this case, the slope m= (-5-7)/(3+2)=-12/5. Hence the equation of a line parallel to this line would be y=mx+c where c is a constant. As this parallel line passes through (4,-2), substituting the values in the equation, we get -2=(-12/5)*4+c.Solving for c, we get
c=(48/5)-2=38/5. The required equation fo the parallel line is thus
y=(-12/5)*x+38/5. Simplifying, the equation would be 12x+5y=38.

Answer 4

slope of 2 lines would be same as they r ||(parallel)

Answer 5

take 2 of the points and do y-y over x-x then thats ur slope!