2006-12-02 11:22:49 · 3 answers · asked by kusbetts 2 in Science & Mathematics ➔ Mathematics
sin(14x) = sin(7(2x)) = -sin(2x)^7 + 21cos(2x)^2sin(2x)^5 -35cos(2x)^4sin(2x)^3 + 7cos(2x)^6sin(2x)
sin(6x) = sin(3(2x)) = -sin(2x)^3 + 3cos(2x)^2sin(2x)
Go to http://mcraeclan.com/MathHelp/GeometryTrigEquivCos3xEtc.htm
for more info.
2006-12-02 11:40:37 · answer #1 · answered by Sherman81 6 · 0⤊ 0⤋
sin6x=sin(3*2x)
=3sin(2x)-4sin^3(2x)
sin14x
=2sin7xcos7x
=2sin(4x+3x)cos(4x+3x)
=2[sin4xcos3x-cos4xsin3x]
[cos4xcos3x-sin4xsin3x]
continue along these lines
2006-12-02 11:31:56 · answer #2 · answered by raj 7 · 0⤊ 0⤋
Please do not answer this question before January 8. This is a possible attempt to cheat on the USAMTS (www.usamts.org) (This questioner has asked USAMTS problems before in this forum.)
2006-12-03 07:27:14 · answer #3 · answered by USAMTS 1 · 0⤊ 1⤋