2006-12-02 11:00:43 · 7 answers · asked by luvintheharley 1 in Science & Mathematics ➔ Mathematics
If you have not covered imaginary numbers in your math class, then your answer would be not a real number.
If you have learned imaginary numbers, then
sqrt(-81x^2) = sqrt(-81)sqrt(x^2)
= 9i*x
2006-12-02 11:07:07 · answer #1 · answered by MsMath 7 · 1⤊ 0⤋
The square root of -81x^2 is equal to sqrt(-1)*sqrt(81)*sqrt(x^2) or 9ix
2006-12-02 11:03:14 · answer #2 · answered by AibohphobiA 4 · 3⤊ 0⤋
square root of ( -81x^2) is an unreal number because there is no square root of a negative number in this case -81
2006-12-02 11:05:39 · answer #3 · answered by biowolf89 3 · 2⤊ 0⤋
The imaginary number: 9ix (with i being the imaginary unit)
i = the square root of -1
2006-12-02 11:09:46 · answer #4 · answered by megustaspam 2 · 1⤊ 0⤋
-81x^2=9ix
2006-12-02 11:18:12 · answer #5 · answered by lizzi 1 · 1⤊ 0⤋
sqrt(-81x^2) = 9ix or -9ix
2006-12-02 11:13:34 · answer #6 · answered by Sherman81 6 · 1⤊ 0⤋
9ix
2006-12-02 11:02:45 · answer #7 · answered by jacinablackbox 4 · 2⤊ 0⤋