Restate the question if you would, doesn't make sense to me. Maybe you mean five traffic lights. If that is so, figureing it out in my head as I do, the chance of the first light being yellow is 1 chance in 3, the chance of the second light being yellow is 1 chance in 3. Multiplying 1 out of 3 by 1 out of 3 would be about 11 chances out of one hundred that the first and second light would be yellow in a row. add the chances of 2nd and third, 3rd and 4th, 4th and fifth, would be about 44 out of one hundred. Of course this is not considering the different amounts of time the different colored lights are on which is not given.
2006-12-02 10:35:29
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answer #1
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answered by Tom B 4
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G'day Stacie c,
Thank you for your question.
Quite high. However it depends on the jurisdiction as there are number of ways of determining when the lights changed. Some systems have a timer when the lights change after a certain period so you can get a sequence of successive lights in a row.
Others have sensor loops to detect traffic so you don't get green lights for empty roads while you have motorists waiting behind reds. There are other systems when the pattern changes according to time of day.
Working out a probability depends on the system in place. However, motorists will say that you have more chance of encountering red or yellow lights if you need to get somewhere quickly.
I have attached sources for your reference.
Regards
2006-12-02 10:40:55
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answer #2
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answered by Anonymous
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Well, you have 5 lights. There are three colors in each one - red, yellow, green.
That means there are three possibilities at each light (red, yellow, or green).
Those three possibilities happen 5 times in a row, so look at it this way: the lights are numbered from 1 - 5.
At light 1, you have a 1 in three chance of hitting yellow. At light 2, again, you have a 1 in three chance of the yellow. That same 1 in three extends to all 5 lights.
Your task is to decide how often the yellow could come up, and then how often it could come up 2 times in a row. (Remember, one possibility is yellow at #1, and red at #2; another possibility is yellow at #1 and green at #2 and so on.)
Hope this helps.
2006-12-02 10:28:58
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answer #3
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answered by Stuart 7
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well, you don't have enough info. You dont say the distance between the lights, the length of the lights(how long they are green, yellow, and red) and the speed that you are driving.
there is a formula for figuring out the probabily of getting 2 out of 5 though. Look up the law of probability
2006-12-02 10:26:21
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answer #4
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answered by ur a Dee Dee Dee 5
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You need more information to get that answer. You have to take into account whether the lights are timed (how long is each light lasting) or are on a spontanious traffic meter. In the case of the latter is it rush-hour/peak drive time?
2006-12-02 10:27:47
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answer #5
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answered by Anonymous
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'what is the probability of catching two yellow lights out of five traffic lights'. read the question carefully the answer is in the question.. it's hard to explain without giving you the answer
2006-12-02 10:32:10
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answer #6
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answered by mbm 2
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depends on the number of times you are at the traffic light. the possibility of getting yellow is 1 out of 3 and you got to factor in the times of each so the amount of time for it to be yellow divided by the total time for it to be red yellow and green. and the probability would be the total of times you are at the light factoral divided by the total minus the yellow lights factoral times the number of yellow lights factoral all that multiplied by the probability of getting one yellow to the (number of times at the yellow light) power times that by the probability of not getting a yellow which is 1 minus the probability of getting a yellow to the (total traffic lights minus the yellow lights) power lol very confusing
2006-12-02 10:30:22
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answer #7
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answered by Cassandra H 2
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8%
2006-12-02 10:30:22
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answer #8
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answered by Bella baby! 2
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i dont understand the question
2006-12-02 10:25:37
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answer #9
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answered by Computer Guy 2
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