Projectile...?

Question

a bullet is fired horizontally @ a speed of 200m/s at a target that is 100m away. help me to calculate:
-how far the bullet has fallen when it hits the target
-the angle that it then makes with the horizontal.

step up step methods plz. thx
i am only intersted in answers that uses suvat equations. acceleration shud be taken as 9.8ms^2

Answer 1

-how far:
The time to get to the target:
t = d/v = 100 m / 200 m/s = .5 s
Distance the bullet will fall during that time:
y = (1/2)*g*t^2 = 9.8 m/s^2 * (.5 s)^2 / 2
y = 1.225 m

-the angle:
The vertical velocity at the target:
Vv = Vo + g*t = 0 + 9.8 m/s^2 * .5 s
Vv = 4.9 m/s

The velocity vector is the resultant of Vv = 4.9 m/s + Vh = 200 m/s. I think you can draw this.

Tan(theta) = 4.9 m/s/ 200 m/s
theta = tan^-1(0.0245) = 1.4 degrees

I hope that helps, I don't know what a suvat equation is.