First add 3 + 4 = 7
Now add 1/2 + 2/5.
The numerator of your sum is 1*5 + 2*2 = 9.
That's the sum of the cross products.
The denominator of your sum is 2*5 = 10.
That's the product of the denominators.
Answer 7 9/10.
You can add any 2 fractions this way.
For example, try 1/2 + 1/3.
Numerator = 3 + 2
Denominator = 2*3
Answer: 5/6.
2006-12-02 09:06:34
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answer #1
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answered by steiner1745 7
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First, convert each mixed number to an improper fraction:
3 1/2 = 7/2 [2x3+1=7], and 4 2/5 = 22/5 [5x4+2=22]. You can now see that the lowest common denominator for these two fractions is 10 [ factors are 2 and 5]...... so the first fraction converts to 35/10 and the second fraction converts to 44/10. Add the numerators together and the total is 79 (over 10) and since 79 is a prime number the answer cannot be reduced any further.
Answer is 79/10 and may also be expressed as 70 9/10.
2006-12-02 07:56:18
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answer #2
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answered by popcorn 3
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Add the whole numbers 3 & 4 to get 7.
Convert the fractions to tenths , so 5/10 + 4/10 = 9/10
Now you have 7 9/10, which, converted to an improper fraction is 79/10.
2006-12-02 07:26:49
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answer #3
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answered by Helmut 7
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what i would do is turn it into an improper fraction, 7/2 + 22/5 then change the demonator into 10 and you get 35/10+44/10 and that equals...79/10 or 7 9/10 hope that was some help
2006-12-02 08:30:08
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answer #4
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answered by shorty_rdb 2
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You make the mixed fractions into improper fractions:
Take 3 1/2 as an example: 3 1/2 = 7/2
Now do the same to the other one and add them together after finding a common denominator.
2006-12-02 07:24:17
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answer #5
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answered by Anonymous
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in case you ever took precalculus or another math type which covers houses of applications, you counsel on the thanks to make certain the area of the function. between the purple flags to seem out for is once you divide with the aid of 0. on your expression, at the same time as x = 3, the denominator is 0. for this reason, the area is each volume beside 3. regrettably, the volume you're trying to plug in (x = 3) is the purely volume that would not paintings in this function. to work out this time-honored hand, you0 can graph this function on a TI-80 3. in case you zoom in on the point of the graph at x = 3, you'll locate there's a sparkling spot there! that is because, as reported above, there purely isn't a fee of the expression at x = 3. you may want to assert, nicely evidently like the answer must be 6, searching on the graph. this theory of what the answer "must be" is what limits are all about. The values of the function on the left and proper of x = 3 all bypass in the direction of 6 as you seize up with and closer. So we are saying the reduce as x is going to three is 6. So even if it isn't technically the answer, 6 is your suited determination. 0 isn't suited in any experience. the very suited answer is to assert that the expression is undefined at x = 3. This challenge illustrates why 0/0 is termed indeterminate. in this challenge, 0/0 in a fashion equals 6. the theory that 0/0 can equivalent something is completely the essence of calculus.
2016-11-23 12:57:56
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answer #6
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answered by ? 4
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You would use 15 2/5. 3 1/2 + 4 2/5 =7/2 x22/5 = 154/10 = 15 2/5. Hope this is what you wanted, question wasn't too clear.
2006-12-02 07:28:25
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answer #7
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answered by ruth4526 7
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te voy a dar una formula como ejemplo vamos a usar 3 1/2
conserve el denominador o sea a 2 luego el 3 multipliquelo por el 2 y sumele 1 el resulatdo es 7/2
luego en la otra conserve el 5 y se realiza el mismo paso el 4 multiplica al 5 y se le suma 2 el resutaldo es 22/5
y luego solo suma 7/2 mas 22/5
2006-12-02 07:28:41
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answer #8
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answered by Andres 4
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Have some PATIENCE and go back to your ORIGINAL question!
I worked it out FOR you there!
http://answers.yahoo.com/question/index?qid=20061202121340AADnP1V&r=w#TJd_UmDpVmZhDVNuaUy5Y9pD7J0FA05sgEwVqi0cD.17xrtpHmz_
And when you're done with your math READ this:
"7. NO REPEATED POSTINGS: You may not post similar or identical postings. This also applies if you are including the same commercial URL on all of your postings for the purpose of directing commercial activity to a non-Yahoo! site. Multiple identical postings, even if legitimate, may be considered spam."
The above is from the Community Guidelines...the BLUE letters to the right of the Answer pane to Answer a question:
http://answers.yahoo.com/info/community_guidelines.php
2006-12-02 07:26:55
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answer #9
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answered by x_southernbelle 7
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