A manufacturer supplies three wholesale businesses, a,b, and c. the output from a day's production is 340 cases of goods. She must send wholesaler a twice as many cases as b. Wholeshaler c gets 20 cases less than wholesalers a and b combines. How many cases of goods should be sent to each wholesaler?
2006-12-02 06:21:32 · 4 answers · asked by Immortal Syther 1 in Science & Mathematics ➔ Mathematics
If a+b+c=340, then let
b=x
a=2x (twice as much as b)
c=2x+x-20 (a+b-20)
therefore,
2x+x+2x+x-20=340
6x-20=340 (add 20 to both sides)
6x=360 (divide by 6 on both sides)
x=60
So the suppliers should each be sent:
a=120
b=60
c=160
Which if you want to check, they all add up to 340 total cases.
2006-12-02 06:29:47 · answer #1 · answered by Valerie 3 · 0⤊ 0⤋
You won't get any better at math by having other people do your homework. At least take a try at it and post what you've done and what you think you could use help with.
2006-12-02 06:24:14 · answer #2 · answered by modulo_function 7 · 0⤊ 0⤋
you wouldn't get any better at math if you don't try and learn from your mistakes.
Good Luck..
2006-12-02 06:32:36 · answer #3 · answered by Vball Babe 3 · 0⤊ 0⤋
a+b+c=340
a=2b
c=a+b-20
c=2b+b-20=3b-20
2b+b+3b-20=340
6b=360
b=60
a=2b=120
c=3b-20=180-20=160
120+60+160=340
a=120
b=60
c=160
2006-12-02 06:25:43 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋