2006-12-02 04:49:30 · 4 answers · asked by lisat2yr 1 in Science & Mathematics ➔ Chemistry
No...not as a structural formula.
C has four bonds available, so two C's would have eight.
If you use three for the H's, five remain...2 1/2 for each carbon...impossible.
Possible 2C hydrocarbons are:
ethane...CH3-CH3...C2H6
ethene...CH2=CH2...C2H4
acetylene...CH---CH...C2H2 (---represents a triple bond)
HOWEVER if you mean C2H3 as an empirical (elemental) formula, then YES.
eg butadiene...CH2=CH-CH=CH2 is C4H6...or C2H3 elemental.
(BTW, if anyone can show me how to type the triple bond on a std keyboard, I would much appreciate the info.)
2006-12-02 05:30:37 · answer #1 · answered by L. A. L. 6 · 0⤊ 0⤋
C2H3 would have an unpaired electron, and it is also known as the vinyl radical, a highly reactive monomer that condenses with itself to form polyvinyl compounds such as PVC. Certainly it exists, but it isn't particularly stable.
2006-12-02 13:05:55 · answer #2 · answered by Black Dog 6 · 0⤊ 0⤋
Transiently at best, but not really a stable molecular arrangement.
The carbon molecule has 4 electrons to share:
H
>C==C-H
H
Only one of these carbons has a stable arrangement, the other carbon still has one electron available for a bond. The incomplete carbon will grab the first H it finds to stabilize.
2006-12-02 12:58:17 · answer #3 · answered by Hank Hill 3 · 0⤊ 0⤋
No; carbon forms 4 bonds (sometimes 2). There is no way to satisfy the bonding of the carbon atoms and produce a stable compound.
2006-12-02 13:00:03 · answer #4 · answered by The Old Professor 5 · 0⤊ 0⤋