y=2/7, x=0
unceasing forgot that the y's were negative to start with
-5y+10/7=-4y+8/7
-y=-2/7
y=2/7
x=0
2006-12-02 03:44:52
·
answer #1
·
answered by txsaxman91 3
·
0⤊
1⤋
If these are two parts of the same question, simply replace one of the X's with the other equation:
5y+10/7=4y+8/7
Thank, subtract the 4y from both sides:
1y +10/7=8/7
Now subtract 10/7 from both sides
y= -(2/7)
So there is your answer
2006-12-02 03:44:51
·
answer #2
·
answered by UnceasingFaun 2
·
0⤊
1⤋
-4y+8/7=-5y+10/7 -4y+5y=10/7-8/7
y=2/7 and x=-4*2/7+8/7=-8/7 +8/7=0...
this is the right answer
2006-12-02 03:48:42
·
answer #3
·
answered by andreea 2
·
0⤊
1⤋
This equation is quite simple.
substitute the top x with the bottom x.
4y + 8/7 = 5y + 10/7.
8/7 = 1y + 10/7
-2/7 = 1y
-2/7 is the answer for y
Now to solve for x just substitute the answer for y into one of the two equations.
x= 4(-2/7) + 8/7
x= -8/7 + 8/7
x= 0
So you could write your final answer like this: (0, -2/7)
2006-12-02 03:52:28
·
answer #4
·
answered by Smart 1
·
0⤊
1⤋
Look and remember!
x=x
-4y+8/7= -5y+10/7
-4y+5y=10/7-8/7
y=(10-8)/7
y=2/7
Then, put ''y'' in one of them.
x= -5*2/7+10/7
x= -10/7+10/7
x=0
Answer:
y=2/7 & x=0
You got it?
2006-12-02 03:57:19
·
answer #5
·
answered by ? 3
·
0⤊
0⤋
x=-4y+8/7
first i guess u do 8 divided by seven and u get 1.142857 with a bar....
so now its
x=-4y+1.142857...
wow i have no idea what's next... ur solving for x and y?
lets try the next one:
x=-5y+10/7
divide by -5 and u get
x=y+10/7....
x=y+1.42857???
2006-12-02 03:51:07
·
answer #6
·
answered by skateKad47 3
·
0⤊
1⤋
x=4y+8/7
x-4y=8/7.......(1)
x=5y+10/7
x-5y=10/7......(2)
subtracting (2)by(1),
x-4y=8/7...(1)
- x-5y=10/7..(2)
+ -
______________
y= -2/7
2006-12-02 03:53:46
·
answer #7
·
answered by Anonymous
·
0⤊
1⤋
In order to solve these equations simultaneously you first need to get rid of one of the unknowns. You do this by subtracting one equation from the other. You then solve to find out what the value which is left is and substiture into one of the original equations to find the second value.
2006-12-02 03:48:46
·
answer #8
·
answered by Anonymous
·
0⤊
1⤋
Solve for y.
x=-4y+8/7
solve for y and then graph is needed.
2006-12-02 03:45:36
·
answer #9
·
answered by smileyface(= 1
·
0⤊
1⤋
Solve for one of them then substitute it in. Such as...
x = 3y + 1
x-1=3y
x-1 (over 3) = y
then bring it in...
x = 3 (x-1 over 3) + 1
then go from there...at least thats what I thought how you do it.
2006-12-02 03:47:43
·
answer #10
·
answered by Anonymous
·
0⤊
1⤋