English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

f(x)= -3(x-2)^2+1

2006-12-02 03:16:35 · 3 answers · asked by johnhildeb 3 in Science & Mathematics Mathematics

3 answers

Vertex: found by taking the negative of the term inside the brackets, and the number outside of the brackets that is either added or subtracted on.

so the answer is (2,1)

The domain is all real numbers.
The range is -infinity up to the vertex. So it's (-infinity, 1)

2006-12-02 03:18:44 · answer #1 · answered by Puggy 7 · 1 0

And the axis is the vertical line going through the middle of the parabola. This line passes through the vertex so it is x=2.

2006-12-02 04:06:47 · answer #2 · answered by Anonymous · 0 0

DOMAIN = all real numbers x,
Range: y=f(x) = -3(x-2)^2+1, then
(x-2)^2 >=0
-3 (x-2)^2 <=0
-3 (x-2)^2 +1 <= 1
so y <=1
.

2006-12-02 03:27:10 · answer #3 · answered by Anonymous · 1 0

fedest.com, questions and answers