2006-12-02 02:57:52 · 10 answers · asked by chinnu 2 in Science & Mathematics ➔ Mathematics
2520
Take the LCM of all these numbers.
2 = 2
3 = 3
4 = 2*2
5 = 5
6 = 2*3
7 = 7
8 = 2*2*2
9 = 3*3
10 = 2*5
LCM = 2*2*2*3*3*5*7 = 2520
2006-12-02 03:03:12 · answer #1 · answered by euclidjr 2 · 6⤊ 0⤋
2520
write
2
3
4 = 2*2
5
6= 2*3
7
8=2*2*2
9=3*3
10=2*5
and think if a number is divisible by 9 it can be divided by 3
and conserve only the number
you have 2^3 3^2*5*7 =2520
2006-12-02 03:57:23 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
2520.
2 and 4 will go into any number 8 will go into. So you can ignore 2 and 4. 3 will go into anything 9 goes into, so you can ignore 3.
6 will sometimes go into whatever 9 goes into.
I multiplied 7, 8, 9, and 5 together, which are most of the leftovers. I came up with 2520, which is also divisible by 6 and 10.
Problem solved.
2006-12-02 03:24:00 · answer #3 · answered by Katri-Mills 4 · 1⤊ 0⤋
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2016-10-17 14:52:08 · answer #4 · answered by pachter 4 · 0⤊ 0⤋
That's the number with only the prime factors of
2,2,2,3,3,5,7, the product of which is 2520. You could have limited the range of answers to a number below 2521 to make it harder.
2006-12-02 03:11:06 · answer #5 · answered by Ben 2 · 0⤊ 1⤋
2520. It´s also divided by 1 (obviously).
2006-12-02 03:16:44 · answer #6 · answered by EAR 1 · 0⤊ 0⤋
find the least common multiple of the given numbers 2,3, ... 10
2006-12-02 03:02:18 · answer #7 · answered by iyiogrenci 6 · 1⤊ 0⤋
2520
2006-12-02 03:15:48 · answer #8 · answered by ssshhh 3 · 0⤊ 0⤋
Hey thats a really good way to do it!!
2006-12-02 03:07:42 · answer #9 · answered by sirprizeme139 3 · 0⤊ 0⤋
I know the answer, but you have no clearance to be told.
2006-12-02 03:11:00 · answer #10 · answered by lulu 6 · 0⤊ 1⤋