If an object is dropped, the distance it falls during t seconds is given by d(t)=1/2 gt squared where g is about 32ft/sec squared. Find the distance an object would fall in 10 seconds
answers can be 3200 ft, 800 ft, 160 ft, or 1600 ft
2006-12-02 00:04:52 · 7 answers · asked by lynn l 1 in Science & Mathematics ➔ Mathematics
just plug in 32 ft/s squared for g, and 10 seconds for time. The answer is 1600.
2006-12-02 00:09:05 · answer #1 · answered by Anonymous · 1⤊ 1⤋
solution: d(t)= 1/2 .32.[(t)2] = 16 x (10x10) =16x100=1600 ft.
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2006-12-02 08:59:39 · answer #2 · answered by Tuncay U 6 · 0⤊ 0⤋
d(t) = 1/2 g t^2
g = 32 ft/s^2
d(10) = 1/2 (32 ft/s^2) * 100 s^2
d(10) = 50 s^2 * (32 ft/s^2)
d(10) = 1600 ft
2006-12-02 08:12:23 · answer #3 · answered by radioflyer 5 · 1⤊ 1⤋
s = 1/2 gt^2 = 1/2 * 10^2 * 32 = 1600ft
2006-12-02 08:16:36 · answer #4 · answered by James Chan 4 · 0⤊ 1⤋
The french dude is the only one that didn't completely do this idiot's problem for them.
In my opinion if you are either that damn lazy, or stupid that you can't do a problem like this then I hope you fail the class.
2006-12-02 08:39:39 · answer #5 · answered by Anonymous · 0⤊ 0⤋
'g' refers to acceleration due to gravity.
The correct value is 9.8 metres per second squared.
Since 1 meter = 3 ft., g = 29.4 ft/sec squared.
1/2 gt squared translates to 0.5*29.4*10*10
Answer = 1470 feet.
2006-12-02 08:09:11 · answer #6 · answered by Pavan M 2 · 0⤊ 4⤋
0.5*32*10²= ?
2006-12-02 08:09:11 · answer #7 · answered by Anonymous · 2⤊ 1⤋