2006-11-30 20:17:02 · 9 answers · asked by veeru 1 in Science & Mathematics ➔ Mathematics
for a triangle sum of 2 sides is always larger than the third side. The measurement given by you fulfills this requirement hence we can easily draw the triangle. Now there is no big deal drawing the parallelogram, most of the other answers like srinivas have stated correctly.
2006-11-30 21:44:51 · answer #1 · answered by balstoall 2 · 0⤊ 0⤋
Possible and very simple too. First construct the triangle ABC with the given three sides. Say AB is the base. Then, draw a parallel line to BC thru A and similarly, a parallel line to AB thru C. The point of intersection of these two parallel lines would be D and ABCD is the required parallelogram.
2006-11-30 20:26:00 · answer #2 · answered by Srinivas c 2 · 0⤊ 0⤋
yes! Draw ab=4cm. With b & a as centres draw 2 arcs each of radius 5.5 & 9 cm to get pt. c. Now c as centre draw cd=ab=4cm & a as centre draw ad = bc=5.5cm because opposite sides of parallelogram are equal.
2006-11-30 22:49:15 · answer #3 · answered by MANDY 1 · 0⤊ 0⤋
Yes, since ca < ab + bc
2006-11-30 20:36:20 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
no
because ac is the diagonal
and ac^2=ab^2+bc^2 for parallelogram
it is not equal as ab=4;bc=5.5;
ac=9
2006-11-30 21:54:17 · answer #5 · answered by riya s 2 · 0⤊ 0⤋
Yes
2006-11-30 20:20:40 · answer #6 · answered by skullmaniac16 2 · 0⤊ 0⤋
No because you listed it as only having 3 sides. Parallelograms have 4
2006-11-30 20:20:39 · answer #7 · answered by King of Slackrs 1 · 0⤊ 3⤋
It is not possible, I draw it my self and two arcs ac and bc are not crossing each other.
2006-11-30 21:24:19 · answer #8 · answered by Atique 3 · 0⤊ 1⤋
yes.
ad=bc and cd=ab
2006-11-30 20:28:34 · answer #9 · answered by Ravi 4 · 0⤊ 0⤋