eliminate the arbitrary constant
1.xy^2-1=cy
2006-11-30 19:25:20 · 8 answers · asked by sheryl 1 in Science & Mathematics ➔ Mathematics
Did anyone ever stop to think that maybe this is just a lil peice of her homework?. Give the girl some credit, she isnt asking for the answer sheet to all of her homework. I wouldnt doubt it if this is one problem she is stuck on and just wants to get it over with, so she can go to bed like a good lil student and be ready for class tomorrow. (lol.. i forgot its thursday, she might want to go out and party too.!)
Hopefully someone with the solution to your problem views this the way i do, and offers you some help.
Cause unless 666 is the answer.. I dont know where to begin on that one
Good luck!
try the links below for some help if all else fails
(sorry, the best i have to offer)
2006-11-30 20:05:44 · answer #1 · answered by satanthdevil 1 · 0⤊ 2⤋
1
2006-11-30 19:37:26 · answer #2 · answered by rparad1 2 · 0⤊ 1⤋
With only one equation of that kind, you'll get for sure two of the constant s you still have in your equation. Or you'll have to assume a value for c or x.
2006-11-30 19:51:23 · answer #3 · answered by fatwesh 2 · 0⤊ 0⤋
xy^2-1=cy
or xy^2-cy-1=0
so y = [c +/- sqrt (c^2+4x)]/2x (using the rule or quadratic equations)
y will have two values.. [c+sqrt(c^2+4x)]/2x and [c-sqrt(c^2+4x)]/2x
:)
2006-11-30 19:48:09 · answer #4 · answered by TJ 5 · 1⤊ 0⤋
Are you learning or depending on others to learn! Learn to stand on your own legs sheryl!
2006-11-30 19:28:45 · answer #5 · answered by Sami V 7 · 1⤊ 1⤋
I can't! I am too sensitive!
2006-11-30 19:32:45 · answer #6 · answered by Anonymous · 0⤊ 1⤋
Do your own homework! :P
2006-11-30 19:39:41 · answer #7 · answered by Anonymous · 1⤊ 1⤋
1,2,3,4,5,6,7,8,9
2006-11-30 19:28:44 · answer #8 · answered by Anonymous · 0⤊ 1⤋