2006-11-30 17:04:56 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
135 / 3 = 45
45 / 3 = 15
15 / 3 = 5
5 / 5 = 1
So the factors are 1, 3, 5, 9, 15, 27, 45, 135
(If you include negative factors, add -1, -3, -5, -15, -27, -45 and -135 too).
2006-11-30 17:07:59 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
1, 3, 5, 9, 15, 27, 45, 135.
1X135
3X45
5X27
9X15
Just divide number by 1, 2, 3, .....Exclude any giving a fraction as a result (like 8, cos it's answer is '16.875'). Once you reach the highest number already used - like 45 above- you're not going to get any more, they'll all have fractions in them. 135/46 = 2.934.. 135/47 = 2.872... 135/48 = 2.8125 135/49 = 0.906
2006-11-30 17:40:36 · answer #2 · answered by Anonymous · 0⤊ 0⤋
135 = 5 * 27 = 5 * 3 * 9 = 5 * 3 * 3 * 3
OK fine, so everyone else seems to think you wanted "all the factors" instead of the "prime factorization".
"All the factors" are every possible combination of the prime factors, plus 1.
So, as they point out, that's: 1 3 5
and then just using the 3s, 3x3 = 9, 3x3x3 =27
And then using the 5s, 5x3 = 15, 5x3x3 = 45, 5x3x3x4 = 135
2006-11-30 17:06:44 · answer #3 · answered by Jim Burnell 6 · 0⤊ 0⤋
135=3^3*5
1, 3, 5, 9, 15, 27, 45, 135
2006-11-30 17:11:17 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋
135 / 3
=45 / 3
=15 / 3
=5 / 5
=1
135=3.3.3.5= 3^3 . 5
the facors of 135 is {1, 3, 9, 27, 5, 15, 45, 135 }
2006-11-30 17:11:45 · answer #5 · answered by iyiogrenci 6 · 0⤊ 0⤋
The answer is 55. 605/55=11 & 275/55=5
2016-05-23 07:04:16 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Just divide by all numbers starting with 1 and see which ones leave no remainder. It's work but it will pay off later when you achieve confidence with numbers.
2006-11-30 17:14:16 · answer #7 · answered by hznfrst 6 · 0⤊ 0⤋