A+B+C+D+E+F+G+H+I = (1+2+3+4+5+6+7+8+9) = 45
17 + (17 - D) + (17 - G) = 45
D+G = 51-45 = 6
so D+G = 6,There are only two choices (4,2) or (5,1)
but 4 is already assigned to A,so take second pair (5,1).
There are again two possibilities
(D,G) = (5,1) and
(D,G) = (1,5).
by trial and error ( by checking the given data)
we get D=5,G=1
2006-12-01 05:11:32
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answer #1
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answered by pradeep gk 1
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A=4, B=6, C=2, D=5,
E=3, F=8,
G=1, H=7, I = 9
is the solution.
2006-12-01 10:28:07
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answer #2
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answered by K M 1
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A=4, B=2, C=6, D=5, G=1, E and F are 3 and 8 in some order, and H and I are 9 and 7 in some order.
So, D = 5, G = 1.
2006-12-01 00:56:29
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answer #3
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answered by stephen m 4
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A=4
B=6
C=2
D=5
E=3
F=8
G=1
H=7
I=9
2006-12-02 00:20:40
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answer #4
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answered by arpita 5
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A=4
B=6
C=2
D=5
E=3
F=8
G=1
H=9
I = 7
2006-12-01 01:41:53
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answer #5
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answered by mr green 4
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Insufficient data. Lot more inf is required.
2006-12-01 00:57:07
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answer #6
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answered by Srinivas c 2
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Thats impossible to answer.
2006-12-01 00:54:45
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answer #7
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answered by chris 2
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What's in it for me?
2006-12-01 00:55:15
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answer #8
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answered by mrquestion 6
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