please solve this compound inequality, if possible please show the work. here it is: -4(x+3) >(this inequality sign is the greater than or equal to sign i just couldn't get the line underneath it) 20 or x-5<(this one is just regular)-2.
2006-11-30 16:14:58 · 14 answers · asked by mhbronc 3 in Science & Mathematics ➔ Mathematics
-4(x+3)>=20 & x-5< -2
-4x-12 >= 20 & x < 5-2
-4x >= 20+12 & x < 3
-4x >= 32 & x < 3
x >= -8 & x< 3
-8 <= x < 3
(x lies between -8 and 3)
2006-11-30 16:43:25 · answer #1 · answered by Anonymous · 0⤊ 0⤋
-4(x+3)>=20
-4x-12>=20
-4x>=32
(when passing the -4 to the other side of the inequality you should change the direction of the inequality sign because you are dividing over a negative number)
x<=-32/4
2006-11-30 16:22:55 · answer #2 · answered by nice.guy22 1 · 0⤊ 0⤋
-4(x+3) ≥ 20 or x-5 < -2
Distribute the -4 in the first part:
-4x-12 ≥ 20
Add 12 to both sides:
-4x ≥ 32
Remember to flip the direction of the ≥ when dividing by a negative number:
x ≤ -8
OR:
(other side)
x-5 < -2
Add 5 to both sides:
x < 3
So, x ≤ -8 or x < 3. Since anything less than or equal to -8 is automatically less than 3, you don't need the first part, so your answer is x < 3.
2006-11-30 16:21:49 · answer #3 · answered by fairyqueen 5 · 0⤊ 0⤋
simplified first unequality
-4 (x + 3) >= 20
x + 3 >= -5
x >= -8
next, simplify second unequality
x - 5 < -2
x < 3
So x must be somewhere between -8 and 3. In other word, x greater and equal than -8 and less than 3. In mathematical we can write as
-8<= x < 3
i hope this can be helpfull
2006-11-30 16:55:00 · answer #4 · answered by Anonymous · 0⤊ 0⤋
-4(x+3)>=20 or x+3 <= -5 or x<=-8; remember when you multiple by a negative number both sides, then you have to change the direction of the inequality
x-5 < -2 or x<3
2006-11-30 16:23:08 · answer #5 · answered by kellenraid 6 · 0⤊ 0⤋
show work :
-4(x+3) > 20 :divide each side by -4
x+3 > 20 : subtract 3 from both sides
x> 17 there ! although as u said, > is equal or greater sign
second problem..
x-5 < -2 : add 5 to both sides
x < 3 there!
hope this helped
2006-11-30 16:21:14 · answer #6 · answered by LOL-sweety_pie-☆ 1 · 0⤊ 1⤋
I think this is how it goes:
-4(x+3)<20 divide both sides by -4, but when you do this, change the way the sign is pointing whenever you multiply or divide both sides by a negative number.
So now (x+3) > -5
subtract 3 from both sides and get x > -8.
For the second part (x-5) < -2.
Add 5 to both sides to get x by itself like the first problem.
So x < 3
2006-11-30 16:21:06 · answer #7 · answered by kdesky3 2 · 1⤊ 0⤋
-4(x+3)>20
First distribute the -4 and get -4x-12>20
Then add 12 to both sides and get -4x>32
Then divide by -4 and get x>-8
x-5<-2
Add 5 to both sides and get x<3
2006-11-30 16:20:58 · answer #8 · answered by Anonymous · 0⤊ 0⤋
Fraction = 1/100 (1 over 100) Decimal = 1% = .01
2016-05-23 06:59:22 · answer #9 · answered by Anonymous · 0⤊ 0⤋
-4(x=3)>20
-4x-12>20
-4x>20+12
-4x/-4>32/-4
x>=-8
x-5<-2
x<3
2006-11-30 16:21:06 · answer #10 · answered by xtenman2000 1 · 0⤊ 0⤋