.
Select * from employee where name like 'D?souza'
**********
Vasu M
**********
2006-11-30 22:57:43
·
answer #1
·
answered by V@su Maniram 3
·
0⤊
0⤋
suppose u r using table emp which has an attribute ename and others so many . u want to know the record of an emp whoose name is D'souza , write down it and execute it
select * from emp where ename ="D'souza"
2006-12-01 00:16:11
·
answer #2
·
answered by Dev 2
·
0⤊
0⤋
Imagine your table name is employee and the field name for storing names of the employee's in the employee table is ename , then the query will be like this.
select * from employee where ename='dsouza';
2006-12-01 01:02:33
·
answer #3
·
answered by mallikj2♠ 2
·
0⤊
0⤋
Is the problem the single quote? Try 'D\'souza'. I'm not an SQL guy, but it's worth a try.
2006-12-01 00:13:56
·
answer #4
·
answered by arbeit 4
·
0⤊
0⤋
Assuming you have a table named table, and a name column named columnname, and the name column contains both first and last names:
For MySQL:
SELECT * FROM table WHERE columnname LIKE '%D\'Souza%'
For Transact-SQL (Microsoft):
SELECT * FROM table WHERE columnname LIKE '%D''Souza%'
2006-12-01 00:18:55
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
Select * from table name
where name like 'D's%'
2006-12-01 00:11:03
·
answer #6
·
answered by albertyakhnin 1
·
0⤊
0⤋
select * from table_name
where name = 'D''souza';
Use two single quotes after D.
2006-12-01 23:57:01
·
answer #7
·
answered by topcat 3
·
0⤊
0⤋
SELECT *
FROM complete
WHERE lName="D'souza";
2006-12-01 01:44:42
·
answer #8
·
answered by techie 2
·
0⤊
0⤋
it's very simple,
Use escape in the query....
2006-12-01 07:12:32
·
answer #9
·
answered by Anonymous
·
0⤊
0⤋
-\displayE "D'souza" end/
2006-12-01 00:07:59
·
answer #10
·
answered by Anonymous
·
0⤊
0⤋