i need the steps to solve the sum. it's urgent?

Question

In town of 500 people, 285 read Hindu and 212 read Indian express and 127read Times of India 20 read hindu and times of India and 29 read hindu and Indian express and 35 read times of India and Indian express. 50 read no news paper. Then how many read only one paper?

Answer 1

H=All reading Hindu, I = All reading IE. T= All reading TOI.
Likewise HT= no of ppl reading H and T both, same way HI and TI.
Draw a venn diagram (a sqaure to represent town of 500, three circles intersecting each other, for each newspaper).

Now Equation will be :
Population = 500 = H + I + T - HI - TI - HT - 2HTI + 50
(when we add H+I+T we are adding HI, TI, HT twice, so subtract once here, same way HTI is added thrice (reading all three papers), so we need to subtract twice. 50 is no of ppl no reading newspaper.
500=285+212+127-29-35-20-2HTI+50
solving for HTI,
HTI = 45.
Now ppl reading exactly one newspaper
= 500-50-29-20-35-45=321.
321 shud be the answer.

Answer 2

Readers of
Hindu = 285
Indian Express = 212
Times of India = 127
H inter I = 29
H inter T = 20
T inter I = 35
No = 50
H inter I nter T = 28

Only one paper:
n(Hindu) = 285 - (20 + 28 + 29) = 285 - 77 = 208 readers.
n(Times) = 127 - (20 + 28 + 35) = 127 - 83 = 44
n(Indian) = 212 - (29 + 28 + 35) = 212 - 92 = 120

General answers:
a) 208 just read Hindu.
b) 208 + 20 + 28 + 29 + 35 + 44 = 364 or
n(A U B) = n(A) + n(B) - n(AinterB) = 285 + 127 - 48 = 364
364 read Hindu or Times.
c) 208 + 20 + 44 + 50 = 322
322 people don't read Indian.
d) 208 + 44 + 48 + 20 + 29 + 35 + 28 + 50 = 462
In town of 500 people, 462 readers had been consulted.
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Is it ok? >>::<<

Answer 3

I must make the assumption that noone reads all three news papers.

The answer is 500 - 50 - 20 - 29 - 35 = 366

Answer 4

Those people who read two newspapers, do they read ONLY two papers, or might some of them read three? hp assumes they read ONLY two papers, and finds the number of (additional) people that must read three to bring the total of readers to 450.

If the readers of two papers also includes the readers of three papers, there can be no more than 20 readers of three papers, and the problem is impossible.