Solve the equation:
-16t(sq) - 28t + 250 = 0
2006-11-30 15:22:16 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Use the quadratic equation
t = -b + or - sqr(b^2 - 4ac)/2a
your equation is already in the form:
at^2 + bt + c = 0
just plug in the variables and solve for t twice
2006-11-30 15:28:13 · answer #1 · answered by ikeman32 6 · 0⤊ 0⤋
-16tsq - 28t + 250=0
first you have to get all of the whole numbers on the same side of the equation.
-16(T2) - 28(t)= -250
this is just to start you off. You need to do your own homework. :)
2006-11-30 15:29:25 · answer #2 · answered by Sissy 3 · 0⤊ 0⤋
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2016-12-13 17:48:31 · answer #3 · answered by mateo 3 · 0⤊ 0⤋
-16t^2-28t+250=0 divide by -2
8t^2+14y-125=0
t=(-14+/-√(14^2+4*8*125))/16
t=(-14+/-√(196+4000))/16
t=(-14+/-√4196)/16
t=-7/8+/-(1/8)√1049)
t=-7/8+(1/8)√1049
t=-7/8-(1/8)√1049
2006-11-30 15:54:29 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋