Finding Roots of Equation: Calculus?

Question

Find the roots of the following:

1 - tan(h)[(2pih)/x]^2

One minus the tangent of 'h' times the quantity: Two pi times 'h' divided by 'x' squared.

Thanks for the help.

Answer 1

assuming h is a real number, we have:
to find roots of any function set it equal to zero
1 - tan(h)*[2*pi*h/x]^2 = 0
tan(h)*[2*pi*h/x]^2 = 1
tan(h)*[4*pi^2*h^2/x^2] = 1
tan(h)*[4*pi^2*h^2] = x^2 x ~= 0 (not equal to zero)
x = +/- sqrt(tan(h))*2*pi*h these are the roots

Answer 2

You have not written an equation. Where's the = sign? Is h a variable or a constant? x?

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