10/15, 14/15, 18/15, 22/15
so the 2nd is 14/15
2006-11-30 14:51:55
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answer #1
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answered by colgatetotalgel 2
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Reminder: an arithmetic sequence is one where the difference between a term and its last is fixed, all the way throughout the sequence. So something like
1, 3, 5, 7, 9
would be an arithmetic sequence, but
1, 2, 4, 8, 16, 32, 64
would not.
In your case, your sequence goes
2/3, ?, ?, 22/15
Convert the 2/3 to having 15 as the denominator.
10/15, ?, ?, 22/15
There's no doubt about it that the two missing numbers are 14/15 and 18/15 (with each term increasing by 4/15)
So the second number in the sequence is 14/15
2006-11-30 22:52:37
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answer #2
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answered by Puggy 7
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first convert the fractions to improper with common denominators....
so the first is 10/15 and the fourth is 22/15
the difference between the two is 12/15 so if you do this with three arithmetic steps, each step is 4/15, therefore the second number is 14/15
2006-11-30 22:57:09
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answer #3
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answered by beatdawookie 2
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