(sq root)2x = (sq root)x-4
2006-11-30 14:32:23 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
√2x=√x-4... first... square both sides of the equation to omit the sq root...
2x=x-4... transpose...
x=-4...
Hope this helps
2006-11-30 14:35:14 · answer #1 · answered by Steph_kinse 2 · 0⤊ 0⤋
The answer depends on which number system you are working on....
If you are working only in real number system, then yes, there are no solutions. Squaring both sides and figuring out the x yields -4. If you put this back into the original formula, you get negative numbers in the square root. This is invalid in real numger system.
If you are working in complex number system (including imaginary number) then -4 is the solution as having negative numbers inside the radical is allowed in this system.
2006-11-30 22:48:48 · answer #2 · answered by tkquestion 7 · 0⤊ 0⤋
is it sqrt(2x) = sqrt(x-4) or is it sqrt(2x)=sqrt(x)-4??
in the former case, there are no solutions. because 2 square roots are equal only when the term inside is equal. and the value of x for which 2x = x-4 is negative, and outside the domain
in the latter case, there are also no solutions.
2006-11-30 22:37:14 · answer #3 · answered by socialistmath 2 · 0⤊ 0⤋
square both sides
2x = x - 4
x = -4
2006-11-30 22:33:47 · answer #4 · answered by deerdanceofdoom 2 · 0⤊ 0⤋
sure.
remind me later, 'mkay?
2006-11-30 22:38:03 · answer #5 · answered by Anonymous · 0⤊ 0⤋