What are the chance of a female with type AB and a male with type A haveing a child with tyoe O?

Answer 1

To answer this question you must look at it through a punnet square.

Mother- I^A I^B
Father- I^A I^A OR I^A i (i = Type O)

The mother being Type AB defines for us each of the alleles that make up here blood type: I^A and I^B.

The father being Type A provides only one clue: that he has at least one A allele. Because an A allele will mask an O allele, it is impossible to know whether or not he has homozygous for Type A blood (I^A I^A) or if he is heterozygous for Type A blood (I^A i). Even as a heterozygote, the father will express Type A blood.

For this reason you must create two separate Punnet Squares. In one the father's genotype will be I^A I^A and in the other his genotype will be I^A i. In both the mother's alleles will remain constant with I^A and I^B.

You will realize, however, that because the mother has no Type O allele (i), there is no possibility that any of their offspring will have Type O blood. This is because Type O blood only appears when both alleles are for Type O (i i). Since the father has possibly one O allele, and the mother has no O allele, a homozygous genotype for Type O blood cannot happen.

Good luck!

Answer 2

A and B are codominant A and B are dominant to O O is recessive to both so genotype for A will be I^Ai or I^AI^A and B will be I^Bi or I^BI^B AB is I^AI^B and O must be ii for there to be an AB baby, it ought to inherit one A and one B so one make sure must be A or AB and the different B or AB if there's a baby with O blood then both father and mother ought to carry that allele. one make sure must be I^Ai (A blood) and the different I^Bi (b blood) to get a AB baby. with those similar father and mother there will be a B baby because it is going to inherit the I^B from one make sure and the i from the different to be B. so sure there will be a AB sibling on condition that the father and mother are heterozygous. one for the I^A allele and the different for the I^B allele. the +/- element is an finished different element edit: the 0.33 sibling does no longer inherit genes from the different siblings, it inherits the alleles for blood form from the father and mother so with the phenotype of the siblings you could purely wager what the father and mother have. it really is why it really is a sure yet on condition that the father and mother are A and B blood kinds and both wearing the recessive allele for O. i comprehend the different solutions that say it really is no longer attainable are incorrect. i took AP biology and learnt each and every of the excuses in the back of it. human beings don't realize that if someone has A blood they often is the service for the O allele and both father and mother have that then they could have a baby with O blood. now if the O male and the B female are the father and mother then the offspring won't be able to be AB. because there is not any A allele to inherit from both make sure.

Answer 3

According to this book I just read to my son, it is definitely not possible. The baby has to be either A, B, or AB. If she were A and you were just B then it could be possible.

Answer 4

the answer can go either way

if both the parents possess no gene for "O" then it's 0%

if one of them possess it, the child will be a carrier

if both of them possess it, 25%

Answer 5

Well if either of you have the gene for o the the chances are pretty good

Answer 6

I believe the answer is 0.Unless outside help is obtained.

Answer 7

no chance... guy could have AO, but O blood need OO, and mom gives A or B... combos could be AO, BO, AB, AA

Answer 8

0 as far as I know - see this link:
http://www.informedcenters.com/Bloodtype.htm

Make sure you scroll down to the parents chart.

Answer 9

zero