I'm divisible by 23 and 3.
Count from 1 to 100, and you'll meet the two-digit number in my thousands and hundreds place just before the two-digit number in my tens and ones place.
I'm greater than 2,000 but less than 9,000.
What number am I?
2006-11-30 13:39:46 · 6 answers · asked by SPECIALVIP 1 in Science & Mathematics ➔ Mathematics
Because 3 and 23 are prime, the number will be a multiple of (3 x 23) = 69.
Next, the two digit number in the thousand and hundreds place must be *just before* the two digit number in my tens and ones place.
The answer is 2829.
You can confirm this by checking the list below:
2001
2070
2139
2208
2277
2346
2415
2484
2553
2622
2691
2760
2829 <--
2898
2967
3036
3105
3174
3243
3312
3381
3450
3519
3588
3657
3726
3795
3864
3933
4002
4071
4140
4209
4278
4347
4416
4485
4554
4623
4692
4761
4830
4899
4968
5037
5106
5175
5244
5313
5382
5451
5520
5589
5658
5727
5796
5865
5934
6003
6072
6141
6210
6279
6348
6417
6486
6555
6624
6693
6762
6831
6900
6969
7038
7107
7176
7245
7314
7383
7452
7521
7590
7659
7728
7797
7866
7935
8004
8073
8142
8211
8280
8349
8418
8487
8556
8625
8694
8763
8832
8901
8970
9039
9108
9177
9246
9315
9384
9453
9522
9591
9660
9729
9798
9867
9936
2006-11-30 13:51:52 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
It is a multiple of 69 then. We check the multiples of 69 that are greater than 2000.
2829 is the number
2829/23 = 123
2829/3 = 943
28 is right before 29
There you have it.
2006-11-30 21:49:42 · answer #2 · answered by dennismeng90 6 · 0⤊ 0⤋
2829
2006-11-30 22:05:32 · answer #3 · answered by Anonymous · 0⤊ 0⤋
2829. Why do you ask?
2006-11-30 22:00:11 · answer #4 · answered by JasonHofmann 1 · 0⤊ 0⤋
Is it 4761?
2006-11-30 21:45:40 · answer #5 · answered by Gomez Addams 4 · 0⤊ 0⤋
2829
Jen
2006-11-30 21:51:46 · answer #6 · answered by InstructNut 4 · 0⤊ 0⤋