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There is a weight of 254.8 Newtons hanging from two ropes. One rope makes an angle with the ceiling with 71 degrees, and the other rope makes an angle with the ceiling with 28 degrees. What is the tension in each rope (use triangle trig, again pic is located below)?

http://i91.photobucket.com/albums/k285/happygolucky2442/Aphg.jpg

thanks in advance. I had 269N and 543N for the ropes, but I am not completely sure.

2006-11-30 12:57:34 · 2 answers · asked by Jer G 3 in Science & Mathematics Physics

2 answers

Let A = ten of rope at 28 deg angle from ceiling
B = ten of rope at 71 deg angle from ceiling

Sum forces in x direction

A cos 28 = B cos 71

sum forces in y direction

A sin 28 + B sin 71 = 254.8

Solving for A & B

B = 254.8/ (tan28 x cos 71 + sin71)

A = B cos 71/ cos28

you crunch the numbers.

2006-11-30 13:08:38 · answer #1 · answered by Roadkill 6 · 0 0

extremely tough problem. lookup onto google or bing. just that could help!

2014-11-07 00:19:30 · answer #2 · answered by ? 3 · 0 0

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