Tension of rope question?

Question

There is a rope that has a weight of 147 Newtons hanging from it. The weight creates two 8 degree angles with where the rope was (straight line) and where it is with the weight on it. How much tension is in the rope (Pretend the rope is weightless, and use triangle trig to figure it out)? I had 1056N, but I dont know if it is 1056 or 528N. Here is a pic of what it would look like:

http://i91.photobucket.com/albums/k285/happygolucky2442/Aphy.jpg

Thanks in advance.

Answer 1

147 Newtons = 2*Tension*sin(8)
Tension = 147/2/sin(8)
The tension in each rope is 528 N.
You probably have the tension in both ropes together, each rope only does half of the holding.
Thanks for the picture, by the way.