Coin problem?

Question

I need this confimred so I'll ask yahoo peple, if you have four coins and you need to find out the total value of all the coins do you multiply 4x4x4x4?

Whoops sorry I actually need to know the total ammount of combonations of 4 coins not the value. like a 1,5,10,and 25 and 1 combo is 1 another is 1 and 5 and 1,5,and 10 and 1 and 10 and so on. Ithink the way to get it is 4x4x4x4

Answer 1

So you can include a coin, or exclude a coin in each combination?

So that would be 2^4 - 1 = 15 combinations
{1}
{5}
{10}
{25}
{1, 5}
{1, 10}
{1, 25}
{5, 10}
{5, 25}
{10, 25}
{1, 5, 10}
{1, 5, 25}
{1, 10, 25}
{5, 10, 25}
{1, 5, 10, 25}

If you can include the empty set { } , then the answer is 2^4 or 16.

Since order doesn't matter then the only thing your worry about is the ways to include or exclude a coin.

There are two ways to include/exclude the penny. There are two ways to include/exclude the nickel. There are two ways to include/exclude the dime. There are two ways to include/exclude the quareter. Multiplying it together you have 2 x 2 x 2 x 2 = 2^4 = 16. But if no coins is not allowed, then you have to subtract 1, for 15 combinations.

Another way to look at is:
C(4,1) + C(4,2) + C(4,3) + C(4,4)

The ways to pick 1 coin, 2 coins, 3 coins or 4 coins from a group of 4 coins. That's 4 + 6 + 4 + 1 = 15 ways (Again assuming that 0 coins is not valid.)

Answer 2

You ADD the value of each coin ..

Say two quarters, a dime and a nickle

25+25+10+5 = 65 cents

Answer 3

if you have four coins of x value, the total would be x+x+x+x, or just 4x

Answer 4

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