please help me with this task:"The length of a rectangle is 1 inch less than twice the width.The area of the r

Answer 1

your question seems to be incomplete.
so far....
width=x
length= 2x-1

Answer 2

which potential the size could be expressed in terms of the width. length = 2(width) - a million section = length * width section = (2(width) - a million)*width section = 2w^2 - w (w = width) 21 = 2w^2 - w 2w^2 - w - 21 = 0 (2w - 7)(w + 3) = 0 w = 7/2 or -3 because of the fact the width won't be able to be destructive, the width is 7/2 inches. The length is then 2(7/2) - a million, or 6 inches. Checking the respond, section = length cases width = 6 * 7/2 = 40 two/2 = 21.

Answer 3

your question appears to be cut off, but I can tell you how to set up your equations
let x equal the length of the rectangle, and y the width
we know that
2y - 1 = x
and you said something about the area, which would be
xy = some number

to solve this, solve the second equation for y
y = some number/x

and substitute it back into the first equation
2(somenumber/x) - 1 = x
this will give you one of your numbers, then solve for the other in one of the given equations

Answer 4

Length =L
width =W
twice width =2W
therefore L=2W-1
Area = W (2W-1)=2W2-W

Answer 5

You can add details if the title is too short, you know.