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Pls answer this quick....................10 pts.................

2006-11-30 12:21:58 · 2 answers · asked by Sunny 2 in Science & Mathematics Mathematics

2 answers

It is notable that the x-intercepts, or solution, of a quadratic equation are known as the ROOTS or the ZEROS of that particular equation.

When you solve a quadratic equation, you are looking for the points that make the equation 0; recall that all problems have one side set to zero. For example:

x^2 + 2x + 1 = 0, the original being y=x^2 + 2x + 1

What you do when you solve the problem is look for the input values of x that give a y value of 0. It is precisely this that produces the effect of a solution being an x-intercept. Continuing:

(x+1)(x+1) = 0, x = -1

What you have done was assume that y=0 (and hence restricted yourself to the x-axis), then tried to find the x points where this
occurs. By setting y=0, you are "searching" along the x-axis; the ssolution is given where the function CROSSES the axis.

2006-11-30 12:31:39 · answer #1 · answered by John H 4 · 0 0

The x-intercepts of a quadratic function are the solutions to the quadratic function when the y value is equal to 0.
ax^2+bx+c=y the x-intercepts are when
ax^2+bx+c=0

2006-11-30 12:25:17 · answer #2 · answered by Nicknamr 3 · 0 0

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