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Write a Balanced equatiion for each of these:
44 A) Ag2 O (s) >>>
B) Nickel (II) Carbonate >>>>>Nickel (II) Oxide + ?
C) Ammonium Nitrate >>>>> Dinitrogen monoxide + Water
48) A) HCl (aq) + Ca (OH)2 (aq) >>>>
B) Ag2 SO4 (aq) + AlCl3 (aq) >>>>(silver chloride is a precipitate)
C) H2C2O4 (aq) + KOH (aq)>>>>
D) CdBr2 (aq) + Na2S (Aq)>>>(Cadium sulfide is a precipitate)
50 Write a Balanced equation for the complete combustion of each compound:
A) Butene (C4H8)
B) Octane (C8H18)
C) glycerol (C3H8O3)
D) Acetone (C3H6O)
52: Complete these:
A) Al (s) + H2SO4 (aq)>>>>
B) HCl (aq) + Ba (OH)2 (aq)>>>>
C) Au (s) + HCl (aq) >>>>>
54) EACH IS BALANCED BUT "INCORRECT", so correct these:
A) Cl2 + NaI >>> NaCl2 + I
B)NH3 >>> N + H3
C) Na+ O2 >>NaO2
D) 2Mg +H2SO4 >>Mg2SO4 + H2
E) MgCl + CaOH >>> MgOH + CaCl
F) H2 + Cl2 >> H2Cl2

2006-11-30 12:16:14 · 2 answers · asked by truckin_90 2 in Science & Mathematics Chemistry

2 answers

A) Ag2O (s) >>> 2 Ag(s) + 1/2 O2 (g)
B) Nickel (II) Carbonate >>>>>Nickel (II) Oxide + [Carbon Dioxide], NiCO3 -> NiO + CO2
C) Ammonium Nitrate >>>>> Dinitrogen monoxide + Water,
C does not balance as is... but this does:
NH3NO3 -> N2O + 1.5 H2O + 0.5 O2

48) A) 2 HCl (aq) + Ca (OH)2 (aq) >>>> 2 H2O + CaCl2 (aq)
B) 3 Ag2 SO4 (aq) + 2 AlCl3 (aq) >>>> 6 AgCl (s) + Al2(SO4)3 (aq) (silver chloride is a precipitate)
C) H2C2O4 (aq) + 2 KOH (aq)>>>> 2 H2O + K2C2O4 (aq)
D) CdBr2 (aq) + Na2S (Aq)>>> CdS(s) + 2 NaBr (aq) (Cadium sulfide is a precipitate)
50 Write a Balanced equation for the complete combustion of each compound:
A) Butene (C4H8): C4H8 + 6 O2 -> 4 CO2 + 4 H2O
B) Octane (C8H18): C8H18 + 12.5 O2 -> 8 CO2 + 9 H2O
C) glycerol (C3H8O3): C3H8O3 + 3.5 O2 -> 3 CO2 + 4 H2O
D) Acetone (C3H6O): C3H6O + 4 O2 -> 3 CO2 + 3 H2O
52: Complete these:
A) Al (s) + H2SO4 (aq)>>>> AlSO4(aq) + H2(g)
B) 2 HCl (aq) + Ba (OH)2 (aq)>>>> BaCl2 (aq) + 2 H2O
C) Au (s) + 3 HCl (aq) >>>>> AuCl3(aq) + 1.5 H2 (g)
54) EACH IS BALANCED BUT "INCORRECT", so correct these:
A) Cl-2 + NaI(aq) >>> NaCl2(aq) + I-
B) NH3(aq) >>> N- + H+3
C) Na (s) + O2(g) >>NaO2(s)
D) 2Mg (s) + H2SO4(aq) >>Mg2SO4(aq) + H2(g)
E) MgCl2(aq) + Ca(OH)2(s) >>> Mg(OH)2(s) + CaCl2(aq)
F) H2 (g) + Cl2 (g) >> H2Cl2 (g)

2006-12-04 05:17:49 · answer #1 · answered by MadScientist 4 · 0 0

1) get the chemical formulae of the compounds involved in the reaction - eg sodium hydroxide is NaOH 2) write out the equations in chemical symbols 3) add up how many of each symbol are on each side of the equation - a subscript number means there are that number of the symbol immediately preceeding it. you cannot change this number. 4) put normal-sized numbers in front of a compound's formula to change how many molecules of that compound are consumed/produced. you may need to change both sides of the equation to get them to balance (use the lowest common multiples you can). here is a worked example: glucose + oxygen = carbon dioxide + water 1&2) C6H12O6 + O2 = CO2 + H2O 3) left: C=6, H=12, O=(6+2)8 right: C=1, H=2, O=(2+1)3 4) if you put a 6 infront of the CO2 you will have the same number of C on each side. then you also have more O on that side, now a total of 13. we will come back to the O in a minute, but first look at the H: 12 on the left, and 2 on the right. so put a 6 infront of the H2O to make the H balance. Now C and H are balanced, and we have an even number of O on the right (18). as there are 6O on the left in glucose, we can just use 18-6=12 to balance the O. it is O2, so we need just 6O2 to make 12 O on the left. so the full balanced equation is: c6H12O6 + 6O2 = 6CO2 + 6H2O. your equations are much simpler than this example, so you should be fine. have a go! good luck...

2016-05-23 06:26:08 · answer #2 · answered by Anonymous · 0 0

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