what is the real value of x which satisfies:
5x + 3 square root x-2=0
please help.
2006-11-30 10:59:48 · 5 answers · asked by P E R S O N 2 in Science & Mathematics ➔ Mathematics
if it is square root of (x-2) then
according to the question x must be >
we have
3 square root (x-2) > 0
5x > 10
=> 5x + 3 square root x-2 > 12 >0
so this equation has no real root
or
let t be square root of x , t here must be > 0
we have : 5t^2 + 3t -2 =0
=> t = -1( <0 not acceptable ) or t = 2/5 ( acceptable )
=> square root of x = 2/5 => x = 4/25
2006-11-30 11:05:44 · answer #1 · answered by James Chan 4 · 0⤊ 0⤋
Are there any parenthesis? The answer will be different if it's (5x+3)^2 (x-2) or 5x+3^2x-2 or any other combination. if it's the first one, x is -3/5 or 2.
2006-11-30 19:06:10 · answer #2 · answered by hodgepodge122 1 · 0⤊ 0⤋
is it 3 times root x;-2 or 3 times root (x-2)?
2006-11-30 19:25:21 · answer #3 · answered by Anonymous · 0⤊ 0⤋
doesnt x always equal to one? sometimes a key is given for what the variable stands for.
2006-11-30 19:01:11 · answer #4 · answered by KelBean 4 · 0⤊ 0⤋
7.
2006-11-30 19:00:49 · answer #5 · answered by Anonymous · 0⤊ 0⤋