write each fraction in simplest form 3*3*3*3*3 divided by 3*3 then tell me?

Question

16ab divided by 20ab*b please help me and tell me how to find out the lcm of 18 and 12

Answer 1

= 16ab/20ab^2
= 4/5b // 16 and 20 can be reduced by 4, and an a and a b cancels out

3*3*3*3*3 = 3^5
3*3 = 3^2
3^5/3^2 = 3^3
= 3*3*3

Answer 2

(1)
3*3*3*3*3 / 3*3 = 3*3*3 = 27

(2)
16ab / 20ab*b =
16ab / 20ab² = (÷ 4ab into top and bottom).
4 / 5b

(3)
lcm or 18 and 12
Break the numbers down into the smallest multiples.
18 = 2*9 = 2*3*3
12 = 2*6 = 2*2*3
Now observe the multiples. Start with the lowest one, it's the 2 in this case. Take the most of them from only one of the numbers - so that 2*2.
Now observe the multiples again. Take the next lowest one, and take the row with the most of them. In this case, it's 3*3.
Now put the multiples together and multiply them together.
2*2*3*3 = 36
36 is the lowest common multiple (lcm), that is, the lowest number that 18 and 12 will divide into evenly.

Answer 3

16ab/20ab*b =2*2*2*2a*b/2*2*5*a*b*b=2*2/5b=4/5b

LCm of 18 and 12
first check divisibility by 2 yes it is and gives the numbers:
2|18,..12
3|9,..6
1|3,..2
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no further common divisiblity so the LCM = 2*3=6