a lady open her cabine, candies felt on the floor, she drop a water jug, 2/5 of the candy got wet and she trew it away, she divided what was left into 3 groups she ate 1 of the groups, then she only had 5candies left. how many did she stared with?
hint: work backward.
2006-11-30 10:44:21 · 6 answers · asked by magiccumbito 2 in Science & Mathematics ➔ Mathematics
Let total no of candies she started with = x
Wasted = 2/5 * x
Left = x- 2/5 x
= 3/5 x
Divide that into 3 groups = 1/3 * 3/5x
= 3/15 x
After 1 group is eaten , left over = 3/5x - 3/15x
=6 / 15x
6/15x = 5
x = 5*15/6
= 12.5
Which should be ~13
2006-11-30 10:54:16 · answer #1 · answered by Ucan win 2 · 0⤊ 0⤋
After eating 1 group, she had 2 groups left. They totaled 5 candies. that would mean 2 1/2 candies per group. I think there is an error here. There should have been an even number left.
2 1/2 candies/group*3groups=7 1/2 candies which was 3/5 of the original total
7.5/.6=12.5 candies to start with.
5 got wet. She ate 2 1/2 leaving 5
2006-11-30 10:51:11 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
Let's make it into an equation...
Let's let C = number of candies:
since she threw away 2/5, she was left with 3/5
then she divided the candies into 3 groups and ate 1, so she had 2/3 left...
C * 3/5 * 2/3 = 5
6/15 C = 2/5 C = 5
2C = 25
C = 12.5 pieces
2006-11-30 10:49:10 · answer #3 · answered by disposable_hero_too 6 · 0⤊ 1⤋
8
2006-11-30 10:50:04 · answer #4 · answered by cutelilprep09 2 · 0⤊ 0⤋
I think there is a problem with this problem
2006-11-30 10:50:57 · answer #5 · answered by Sam P 2 · 0⤊ 0⤋
you obviously know how to do it, so just do it.
2006-11-30 10:51:33 · answer #6 · answered by Kristina M 2 · 0⤊ 0⤋