2006-11-30 10:36:27 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
sin 90 = 1, right?
40/sin A = 70, so
sin A = 40/70 = 4/7
A = arcsin(4/7)
2006-11-30 10:38:43 · answer #1 · answered by Jim Burnell 6 · 0⤊ 0⤋
sin 90 = 1
40 = 70 sin A
sin A = 40/70 = 4/7
2006-11-30 18:38:12 · answer #2 · answered by Modus Operandi 6 · 0⤊ 0⤋
40/Sin A = 70/Sin 90 <=>
sin A = 40/70 <=>
A = Arcsin (40/70) or A = 180 - Arcsin(40/70) <=>
A= 34.8 or A = 145.2
Technically, you can add or subtract 360 to both the above numbers and find solutions that will satisfy that equation. I assume that you are only interested in angles that are between 0 and 360 degrees
2006-11-30 18:54:59 · answer #3 · answered by Ivan 5 · 0⤊ 0⤋
40/sin A = 70/sin 90
40/sin A=70/1
sin A=40/70
A=arcsin (40/70)=34.85°
2006-11-30 18:43:02 · answer #4 · answered by Yvonne L 1 · 0⤊ 0⤋
40/sin A = 70/sin 90
40/sin A=70/1
sin A=40/70
A=arcsin (40/70)=34.85°
2006-11-30 18:39:26 · answer #5 · answered by yupchagee 7 · 0⤊ 0⤋
Angle A = arcsin(40/(70/sin90)) = arcsin(40/70) because sin90 = 1. A = 34.
2006-11-30 18:48:50 · answer #6 · answered by Dracula 2 · 0⤊ 0⤋
sin 90=1
40/sinA=70
40/70=sinA
A=arcsin40/70
2006-11-30 18:39:11 · answer #7 · answered by pzratnog 3 · 0⤊ 0⤋