Given a right Triangle with a hypotenuse of 13 and a leg of 7, find the length of the other leg to three decimal places.
2006-11-30 09:43:19 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Use the Pythagorean Theorem of:
a² + b² = c²
a and b are legs, c is the hypotenuse.
Putting in the numbers you know:
7² + b² = 13²
Now solve for b:
b² = 13² - 7²
b² = 169 - 49
b² = 120
Take the square root:
b = sqrt(120)
b ≈ 10.954
2006-11-30 09:45:08 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
use the pathagrium theorum which is A^2 + B^2 = C^2
7^2 + B^2 = 13^2
so then 169-49 = 120.
Square root of 120 is 10.954 so thats the other legs length
2006-11-30 17:46:58 · answer #2 · answered by ncaafan2 2 · 0⤊ 0⤋
a^2 + b^2 = c^2
7^2 + b^2 = 13^2
49 + b^2 = 169
b^2 = 169-49
b^2 = 120
Take the square root of 120
10.954
2006-11-30 17:54:44 · answer #3 · answered by bugjrmom 3 · 0⤊ 0⤋
13^2 - 7^2 = 120
The square root of 120 = 10.954
2006-11-30 17:46:06 · answer #4 · answered by MollyMAM 6 · 0⤊ 0⤋
7^2 + b^2 = 13^2
49 + b^2 = 169
b^2 = 120
b = square root of 120
b = 10.954
2006-11-30 17:47:35 · answer #5 · answered by mysteriosa 1 · 0⤊ 0⤋