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1) Is square root x squared =x (true for all values of x)? Explain your answer.

2). For the function, y= 1/x-1. Give the y values for x= -2,1,0,1,2,3. Show work please.

2006-11-30 09:25:36 · 4 answers · asked by csmitty 1 in Science & Mathematics Mathematics

4 answers

1) First, you can't square root a negative, so sqrt(-3) = impossible. sqrt and ^2 (squared) are inverse functions, they undo one another. The sqrt(49)=7, and 7^2=49, and sqrt(49)^2=49. This will work for all number > or = to zero.

2) Plug in x values:
y=1/-2-1=1/-3
y=1/-1-1=1/-2
y=1/0-1=1/-1=-1
y=1/1-1=1/0=undefined (impossible)
y=1/2-1=1/1=1
y=1/3-1= 1/2

2006-11-30 09:43:55 · answer #1 · answered by patdacat115 2 · 0 0

1. When x is a negative number, it will not be true.
The square root of (-5)^2 = 5, not negative 5

2. Substitute
-1/3, undefined, -1,undefined (again), 1, 1/2

I'm thinking you mean -1 for the second value. In that case it's -1/2

2006-11-30 17:40:55 · answer #2 · answered by MollyMAM 6 · 0 0

I can only help with question # 2

x= -2; y=-1/3
x= 1; y= 0
x= 0; y= -1
x= 2; y = 1
x= 3; y= 1/2

2006-11-30 17:46:07 · answer #3 · answered by samba 1 · 0 0

1. No. sqrt (-3) squared is 3, not -3

2006-11-30 17:32:28 · answer #4 · answered by hayharbr 7 · 0 0

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