Find the first second and third derivate of y=7x^2 + (1/x) +e^(2x)?

2006-11-30 08:40:54 · 2 answers · asked by km 1 in Science & Mathematics ➔ Mathematics

y = 7x^2 + x^-1 + e^(2x)
y' = 14x - x^-2 + 2e^(2x)
y'' = 14 + 2x^-3 + 4e^(2x)
y''' = -6x^-4 + 8e^(2x)

2006-11-30 08:45:11 · answer #1 · answered by MsMath 7 · 4⤊ 0⤋

14x - 1/x^2 + 2e^(2x)
14 + 2/x^3 + 4e^(2x)
-6/x^4 + 8e^(2x)

2006-11-30 16:44:42 · answer #2 · answered by Nicknamr 3 · 1⤊ 0⤋

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