How do you find the perimeter and area of a right triangle?

Answer 1

Given sides A and B, the hypotenuse is Sqrt(A^2+B^2), so that the perimeter is A + B + Sqrt(A^2+B^2), and the area is 1/2 AB.

Answer 2

Let the base of triangle= b
Vertical side =h
Hypotenuse= l
l=square root of (h to the power2 +b to the power 2 )
Perimeter = b + h + l
Area = (1/2)b * h

Answer 3

perimeter of a right-triangle uses the Pythagorean Theorem, A-squared+B-squared = C-squared.

a right triangle is basically half of a square, so you just do the same thing you would to find the area of a square, but divide your answer by 2

Answer 4

perimeter=l1+l+h where l1 andl2 arethe legs an h hypotenuse
area=(1/2)l1l2

Answer 5

A= base x height / 2
P= s1 +s2 +s3

Answer 6

I found this site to be helpful.

http://mathworld.wolfram.com/RightTriangle.html

Hope it helps you. As can be seen, both answers to your question are given.