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Graph the following equation by finding and plotting intercepts.

2X - 3Y = 7

2006-11-30 06:45:21 · 7 answers · asked by dnice1042 1 in Science & Mathematics Mathematics

7 answers

yes!

2x-3y=7

-2x from each side of the =

-3y=-2x+7

-3y/-3 and -2x+7/-3

y=2/3x+-2.3

Go to -2.3 on the Y-intercept
The slope is 2/3 (up 2, over 3)

2006-11-30 06:58:04 · answer #1 · answered by gabster 2 · 0 0

To find an intercept you need to substitute 0 for one of the variables then solve for the other, then do this again but use 0 for the second variable.

So to find the x-intercept substitute y=0 into the equation and solve for x:

2x - 3(0) = 7
x = 3.5
therefore the line intercepts the x=axis at x = 3.5 (plot the point (3.5,0)

For the y-intercept:
2(0) - 3y = 7
y = -7/3 = -2 1/3

So plot a point on the y=axis at -7/3.

Now connect the two points and you are done!

2006-11-30 06:56:40 · answer #2 · answered by Kaedence 2 · 0 0

to discover an intercept you want to replace 0 for between the variables then remedy for the different, then attempt this back yet use 0 for the 2d variable. with the point to discover the x-intercept replace y=0 into the equation and remedy for x: 2x - 3(0) = 7 x = 3.5 hence the line intercepts the x=axis at x = 3.5 (plot the point (3.5,0) For the y-intercept: 2(0) - 3y = 7 y = -7/3 = -2 a million/3 So plot a level on the y=axis at -7/3. Now connect both factors and also you're finished!

2016-10-08 00:35:41 · answer #3 · answered by Anonymous · 0 0

-3y = -2x + 7
y= 2/3x - 7/3

Now.. Plug numbers in for X (multiply that number by 2/3 then subtract 7/3) and see what Y equals. Then graph the numbers you got onto your graph.

I.E. Plug 3 in for X.. Then you'll have y = 2 - 7/3 which = -1/3..Graph (3, -1/3) on your graph.

2006-11-30 06:57:32 · answer #4 · answered by immageek 1 · 0 0

Rearrange the equation to give:

y = (2/3)x - 7/3

From this, it's clear that the y-axis intercept is at (0,-7/3), the x-axis intercept is at (7/2,0), and the gradient is 2/3.

Hope that helps!

2006-11-30 06:56:39 · answer #5 · answered by Sangmo 5 · 0 0

Search for the site "geogebra".It is free and you can do many things in mathematics through this site.

2006-11-30 06:52:59 · answer #6 · answered by andelska 3 · 0 0

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