w^2-w = w( )
2006-11-30 04:01:54 · 4 answers · asked by kris10 1 in Science & Mathematics ➔ Mathematics
w(w-1)
2006-11-30 04:03:15 · answer #1 · answered by jennytkd13 3 · 1⤊ 0⤋
w^2-w = w( )
w^2-w = w(w-1)
(and the expression in the parenthesis is w-1)
Work:
note that w^2 = w*w, so the w^2 - w
can be expressed also as w*w - w!
Now, on the left, extract the common multiplier from both w^2 and w:
w(w-1)
you get:
w(w-1) = w()
since w = w,
(w-1) = ()
the expression in parenthesis is w-1, and the solution is:
w^2-w = w(w-1)
2006-11-30 14:52:07 · answer #2 · answered by Mirta G 2 · 0⤊ 0⤋
w^2-w = w( )
We're looking for the Greatest Common Factor, GCF.
In this case, w^2-w has a GCF=w.
w[(w^2)/w - w/w]
Simplify & Reduce:
w(w-1)
ANSWER:
w^2-w = w(w-1)
2006-11-30 12:26:53 · answer #3 · answered by LovesMath 3 · 0⤊ 0⤋
(w-1)
2006-11-30 12:06:05 · answer #4 · answered by ? 3 · 0⤊ 0⤋