Well, first consider how many way with one 5 and five ones.
You have ((10*9*8*7*6)/(5!)) = 252 different ways having 5 ones,
and 2 different ways with both the 5's.
So, thats 252*2 = 504 ways with 1 five and 5 ones.
Then with both the fives that would be 1, and 10 ones, that would be one.
So, thats 504+1+1 = 506 total ways.
2006-11-30 03:43:15
·
answer #1
·
answered by yljacktt 5
·
0⤊
0⤋
1) 2 * 5 = 10
2) 5 + 5 * 1 = 10
3) 0*5 + 10 * 1 = 10
This was done just using logic.
This is equation with 2 unknowns....
antX * X + antY * Y = SUM
We want to solve how many ways, then we give the value....
5X + Y = 10
This is the formula...
X is the number of $5, Y is the number of $1
Start with:
Y = 0
Solve it:
5x + 0 = 10
x = 10/5 = 2
1) 2 * $5 is $10
Now you just have to try different values for Y, by just increment it. When SUM is greater than 10, you have found all the posibilities....
If you know how to program a calculator or something, this kind of equation is easy to solve...
2006-11-30 11:33:19
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
lets say the fiver is represented by F and the dollar by D:
5F+D=10
simple
2006-11-30 11:17:55
·
answer #3
·
answered by pito16places 3
·
0⤊
0⤋
sounds like a deadbeat dad if that's all he can afford to give his kids
2006-11-30 11:17:30
·
answer #4
·
answered by jivesucka 6
·
0⤊
2⤋