how many moles of sodium hydroxide are there in 500cm3 of a 1M solution? if 500cm3 of 1M sodium hydroxide is required to neutralise 50ml of a sulphuric acid solution what is the molar concentration of the acid?
2006-11-30 02:29:52 · 4 answers · asked by celcia d 1 in Science & Mathematics ➔ Chemistry
2NaOH + H2SO4 = Na2SO4 +2H2O Sodium Hydroxide is 0.5moles.Two Moles neutralise One mole of Acid. 0.5Moles neutralise of Alkali neutralises 0.25Moles of Acid 50mls of 1M SULPHURIC ACID = .05M THEREFORE MOLAR CONCENTRATION IS 5
2006-11-30 02:52:56 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I work out that the balance for those two chemical agents are roughly 3 parts sodium hydroxide to one part sulphuric acid.
Carefull with it - it gave me lovely blonde streaks in my black hair, but ruined a patch of the carpet.
Not a wise thing to fiddle with, however, add a touch of nitric acid, and a good gloop of glycerin.
Oh dear, perhaps I shoud not be sending this, as it goes bang in a big way. Nitro-glycerin.
Don't shake it up after simmered in a pan.
Just good fun in remote places in the Mid-East.
2006-11-30 10:51:45 · answer #2 · answered by Bob the Boat 6 · 0⤊ 0⤋
0.5 M of NaOH.
H2SO4 is di-protic, will need 2 mols of naoh to neutralize per 1 M h2so4.
TF..
[h2so4] = 10 M
2006-11-30 10:39:20 · answer #3 · answered by luke c 1 · 0⤊ 0⤋
2NaOH + H2SO4 --> Na2SO4 + 2H20.
500cm3 x _1L___ x _1mol____= 0.5 mol
1000cc 1L
(500 )/(2x50 )= 5 molar
2006-11-30 11:40:23 · answer #4 · answered by docrider28 4 · 0⤊ 0⤋