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Imagine a lightweight, almost massless meterstick, with a 5 kg mass at each end (like a dumbbell). How much torque would be needed to give this object a rotational acceleration of 6 rad/s2 about its midpoint?

2006-11-30 02:02:43 · 2 answers · asked by James R 1 in Science & Mathematics Physics

2 answers

its momentum of inertia is J=2* 5*(0.5^2)=2.5
like F=m*a, C(torque)=J* dw(rotational acceleration)
so C=2,5*6=30 [N*m]

2006-11-30 02:20:53 · answer #1 · answered by sparviero 6 · 0 0

use this link

http://www.engineersedge.com/motors/calculator/accelerating_torque_force_general.htm

2006-11-30 02:23:35 · answer #2 · answered by levent d 4 · 0 0

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