let us assume two rocks both at same cliff with the same mass are pushed down.continued in the add. detail?

Question

let us assume two rocks both at same cliff with the same mass are pushed down.one falls down on an elevated platform just below the cliff and another all the way down.
the force in both the cases will be the same as the mass is the same and the acceleration due to gravity is also the same as f=ma.but the damage caused to the platform by the stone which falls on it is surely less when compared to the damged caused by the stone which falls all the way down on the ground below the platform.why is this so?

Answer 1

TERMINAL VELOSITY

Answer 2

The damage caused by the two falling stones will be determined not by the force acting on them at the time of impact, but rather by the velocity or speed with which they strike the platform or ground. The velocity of an object falling under gravity is determined by the equation: V*V = U*U + 2*g*h, where V = velocity after falling height h, U= initial velocity, g= acceleration due to gravity. In our case , U=0. V = SQRT(2*g*h)
It follows therefore that the velocity of impact of the stone on the ground will be higher than that on the platform, since hg > hp.
The actual damage is further determined by the momentum of the falling rocks, given as M = V*m, where M = momentum, m = mass.

Answer 3

the acceleration due to gravity is not the same. the one that falls further down has been falling for a longer period of time and gravity has accelerated it more.

Answer 4

potential energy..

f=m.g.h

you have to calculate f according to their height from the base level. at every level, it has different potential energy, and the loss energy is just turned into kinetic energy.. which makes that damage..

Answer 5

the longer your swing the harder the punches
try it in bowling and you can understand more