(a) (-30x^3y^5) + (16x^3y) - (10xy^3) / (-4xy^3)
show working please
2006-11-30 01:52:24 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
-30x^3y^5=2xy(-15x^2y^4)
16x^3y=2xy(8x^2)
-10xy^3=2(-5xy^2)
so the expression
2xy(-15x^2y^4+8x^2-5xy^2)/-4xy^3
=-(1/2y^2)[-15x^2y^4+8x^2-5xy^2]
2006-11-30 01:59:45 · answer #1 · answered by raj 7 · 1⤊ 0⤋
(-30x^3y^5) + (16x^3y) - (10xy^3) / (-4xy^3)
= -2x^3y(15y^4 - 8) + 2.5
In the first two terms, we simply factor out the common term 2x^3y.
In the last term the xy^3 cancel out leaving -10/-4 = +2.5
2006-11-30 02:09:50 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
(-30x^3y^5) + (16x^3y) + 5/2
x^3y(16-30y^4)+5/2
minor point - it's not an equation.
2006-11-30 01:59:27 · answer #3 · answered by Anonymous · 0⤊ 0⤋
http://www.algebrahelp.com/calculators/expression/oops/
try this it helps me maybe it can help you
2006-11-30 01:59:21 · answer #4 · answered by Anonymous · 0⤊ 0⤋
do your own homework kid
2006-11-30 01:59:24 · answer #5 · answered by tyrebrnr21 2 · 0⤊ 0⤋