2006-11-30 01:09:38 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
square root of 2x+3=6
<=> 2x+3 = 36
<=> x = 33/2
2006-11-30 01:12:24 · answer #1 · answered by James Chan 4 · 0⤊ 1⤋
If the square root is on the 2x + 3 only then it is an easy problem
What you ahve to do is square both sides of the equation this eliminates the square root on the left side.
You are then left with
2x + 3 = 36
then all you have to do is solve
2x + 3 = 36
minus 3 from both sides
2x = 33
divide by 2
x = 33/2 or 16.5
2006-11-30 09:14:58 · answer #2 · answered by steve0stac 2 · 0⤊ 0⤋
you can start by squaring both sides to get rid of the square root.
(square root (2x + 3)) ^2 = 6^2
2x + 3 = 36
Now, you can subtract 3 from both sides
2x = 33
Now divide both sides by 2
x = 33/2 or 16.5
2006-11-30 09:14:42 · answer #3 · answered by Krisie 2 · 0⤊ 0⤋
2x+3=6
square root of 2x+3= 6 i.e 6^2=36
=2x+3=36
=2x=36-3
=2x=33
=x=33/2
=16.5
2006-11-30 09:16:06 · answer #4 · answered by virendra s 2 · 0⤊ 0⤋
squaring both sides
2x+3=36
2x=33
x=33/2
=16 1/2
if your sum is (2x)^1/2+3=6
(2x)^1/2=3
squaring
2x=9
dividing by 2
x=9/2
=4 1/2
2006-11-30 09:13:17 · answer #5 · answered by raj 7 · 0⤊ 0⤋