2006-11-30 00:42:45 · 6 answers · asked by lahingesudraz 1 in Science & Mathematics ➔ Chemistry
It is not an redox or acid-base reaction. so you can't employ oxidation number method or ion-electron method. So the options you have left are the inspection method & algebraic method. Among them, I think this equation is way too simple to employ algebraic method.Why don't you employ the simple inspection method.
C2H5OH-----------> Oh! BY THE WAY! WHAT IS HCO2. THERE IS NO SUCH COMPOUND AS THIS.
However the possible products are:-
C2H5OH----------------->CH3CHO + H2(Cu,300deg C)
C2H5OH----------------->H2CCH2 + H2O(H2SO4,170 deg. C)
C2H5OH----------------->C2H5OC2H5(H2SO4,140 deg. C)
C2H5OH----------------->H2CCH2 + H2O(Al2O3,300 deg. C)
C2H5OH----------------->H2CCH2 + H2O(H3PO4,250 deg. C)
2006-11-30 00:52:55 · answer #1 · answered by s0u1 reaver 5 · 0⤊ 0⤋
Hmmm...You probably wrote down the equation wrong. There's one one too many bonds in your reactant, you could have either C2H6 or C2H5O. HCO2 is also not a compound. The equation probably is
C2H6 + O2 .....> CO2 + H2O
Because carbon groups reacts with oxygen to produce Carbon Dioxide and water in a complete combustion.
If that was the equation it would be
C2H6 + 3.5*O2 .....> 2*CO2 + 3*H2O
2006-11-30 04:58:19 · answer #2 · answered by dwn001 2 · 0⤊ 0⤋
C2H5OH------> C2H4+H2O
2006-11-30 00:55:17 · answer #3 · answered by Anonymous · 0⤊ 0⤋
This is not a real reaction. double check, i'm pretty sure there is no such compound as HCO2
2006-11-30 04:26:14 · answer #4 · answered by arbus 2 · 0⤊ 0⤋
Go to an equation balencer on the internet
2006-11-30 00:44:43 · answer #5 · answered by Anonymous · 0⤊ 0⤋
C2H5OH _____ CH2 + H2O + CH+
lol....i forgot.
2006-11-30 01:04:39 · answer #6 · answered by ? 7 · 0⤊ 0⤋